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4
2x-3[x-(4x+1)]=1-x+1
2x-3[x-4x+1]=1-x+1
2x-3x+12x-3=1-x+1
2x-3x+12x+x=3+1+1
12x=5/:12
x=0,4
b) ⅔ ( 3x - 1 ) - trzy drugie [ 2x + 3(x - 2)] = 1 /×6
4(3x-1)-9[2x+3(x-2)]=6
12x-4-9[2x+3x-6]=6
12x-4-18x-27x+54=6
12x-18x-27x=6-54+4
-57x=-44/: (-57)
x=1,2