a)
(x-3)(2x+6)=0
(x-3)·2·(x+3)=0|:2
(x+3)(x-3)=0
x+3=0 ∨ x-3=0
x=-3 ∨ x=3
x∈{-3,3}
b)
-2x(x-5)=0|:(-2)
x(x-5)=0
x=0 ∨ x-5=0
x=0 ∨ x=5
x∈{0,5}
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a)
(x-3)(2x+6)=0
(x-3)·2·(x+3)=0|:2
(x+3)(x-3)=0
x+3=0 ∨ x-3=0
x=-3 ∨ x=3
x∈{-3,3}
b)
-2x(x-5)=0|:(-2)
x(x-5)=0
x=0 ∨ x-5=0
x=0 ∨ x=5
x∈{0,5}