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a)
-5xdo4 +3xdo3 +14xdo2 =0
x2(-5x2 +3x +14) =0
x2 = 0,
Xo = 0,lub
-5x2 +3x +14 = 0
D.=9 + 280 = 289
VD =17
X1 = (-3-17)/:(-10) = -20/(-10) =2
X2 =(-3 +17)/:(-10) = 14/(-10) = -1,4
b)
4xdo4 -5xdo2 +1 = 0
podstawiam : t = x2
4t2 -5t +1 =0
D =25 -16 =9
VD =3
t1 =(5-3)/8 =1/4
t2 =(5 +3)/8 =1
powracając do podstawienia mamy:
x^ =1/4,to
X1 = -1/2
X2 =1/2,
t2 =1,
X3 = -1
X4 =1