rozwiąż równania .
a) 3(x+3)=2(x+4)+x+1
b) 2)x-4)=2(2x-1)+6(x+1)
błagam ! :******
3(x+3)=2(x+4)+x+1
3x+9=2x+8+x+1
3x-2x-x=8+1-9
0=0
2(x-4)=2(2x-1)+6(x+1)
2x-8=4x-2+6x+6
2x-4x-6x=-2+6+8
-8x=12//(-8)
x=-1,5
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3(x+3)=2(x+4)+x+1
3x+9=2x+8+x+1
3x-2x-x=8+1-9
0=0
2(x-4)=2(2x-1)+6(x+1)
2x-8=4x-2+6x+6
2x-4x-6x=-2+6+8
-8x=12//(-8)
x=-1,5