Question

Rozwiąż równania: a) 2x+2(3x+1)=10 b)(X-2)(X+3)= X do kwadratu

Answer 1

a)

2x+2(3x+1) = 10

2x+6x+2 = 10

8x+2 = 10

8x = 10-2

8x = 8 |:8

x = 1

 

b)

(x-2)(x+3) = x²

x²+3x-2x-6 = x² |-x²

3x-2x-6 = 0

x-6 = 0

x = 6

Answer 2

 a) 2x+2(3x+1)=10

2x+6x+2=10

8x=10-2

8x=8|:8

x=1

 b)(X-2)(X+3)= X²

x²+3x-2x-6=x²

x²-x²+x=6

x=6