February 2019 0 36 Report
Rozwiąż równania.
6 (3y+2)-5 (4y+6)=-6

-7(2z-3)-5 (4-3z)=1

0=-8 (x+3)+4 (2x-6)

3=-3 (5y+2)+6 (3y-7)

2 (7x-3)=5-4 (6-4x)

2 (7y-1)-3(2y+1)+1=5 (4y+3)

More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.