August 2018 1 15 Report
Rozwiąż równania
(2x-1)(2x+1)+6=4(x-4)do2 +3x
(4x+3)do2+10=(4x-1)(4x+1)+4x

zad2
(x-5)do2-2=x(x-2)-(x-1)\2
(3x-1)do2-(2x+1)\3=9x(2+x)-8(x+2)
(x+4)do2+(x+8)\2=½x(2x-6)+(x+1)
(2x-1)do2+5=4x(x-2)-2(2x+1)
\-kreska ułamkowa
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