rozwiąż reakcję tlenku glinu z kwasem siarkowym VI
Al₂O₃ + 3H₂SO₄---->Al₂(SO₄)₃ + 3H₂O
Al₂O₃ +3H₂SO₄ = Al₂(SO₄)₃ + 3H₂O
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Al₂O₃ + 3H₂SO₄---->Al₂(SO₄)₃ + 3H₂O
Al₂O₃ +3H₂SO₄ = Al₂(SO₄)₃ + 3H₂O