September 2018 1 21 Report

Rozwiąż podane nierówności :

x(x+1)-(x^2+1)<2(-x+3)

 \frac{3(x-1)^2}{2} - \frac{2(x+3)^2}{3}< \frac{5(x^2-8x-3)}{6}

\frac{(x-2)^2}{2} - (x+2)(x-2)\leq 8- \frac{(x+2)^2}{2}

Z Góry dzięki


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