Rozwiąż nierówność:
(x-2)(x-5)<(równe)4
x²-7x+6≤0
Δ=49-4*1*6=25
√Δ=5
x1=(7-5)/2=1
x2=(7+5)/2=6
x∈<1;6>
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(x-2)(x-5)<(równe)4
x²-7x+6≤0
Δ=49-4*1*6=25
√Δ=5
x1=(7-5)/2=1
x2=(7+5)/2=6
x∈<1;6>