Rozwiąź nierówność.
tylko podpunkty:
e)
f)
(x - 3)/2 < (x +2)/3 /*6
3(x - 3) < 2(x +2)
3x - 9 < 2x + 4
3x - 2x < 4 + 9
x < 13
(2 - x)/5 < (x + 1)/2 /*10
2(2 - x) < 5(x + 1)
4 - 2x < 5x + 5
-2x - 5x < 5 - 4
-7x < 1 /:(-7)
x > -1/7
e) (x-3)/2 < (x+2)/3 /*6(wtedy pozbedziemy sie ulamkow)
3x-9<2x+4 /-4
3x-13<2x /-3x
-13<-x /:(-1)
13>x
f) (2-x)/5<(x+1)/2 /*10
4-2x<5x+5 /-4
-2x<5x+1 /-5x
-7x<1 /:(-7)
x>- 1/7
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(x - 3)/2 < (x +2)/3 /*6
3(x - 3) < 2(x +2)
3x - 9 < 2x + 4
3x - 2x < 4 + 9
x < 13
(2 - x)/5 < (x + 1)/2 /*10
2(2 - x) < 5(x + 1)
4 - 2x < 5x + 5
-2x - 5x < 5 - 4
-7x < 1 /:(-7)
x > -1/7
e) (x-3)/2 < (x+2)/3 /*6(wtedy pozbedziemy sie ulamkow)
3x-9<2x+4 /-4
3x-13<2x /-3x
-13<-x /:(-1)
13>x
f) (2-x)/5<(x+1)/2 /*10
4-2x<5x+5 /-4
-2x<5x+1 /-5x
-7x<1 /:(-7)
x>- 1/7