rozwiąż nierównosći
A) x-π≥xπ
B) πy-2<3y+4
C) (√3-1)(√3+1)x≥4√3x-10
A) x-pi>=xpi
x-xpi>=pi
x(1-pi)>=pi
x>=pi/(1-pi)
B) piy-2<3y+4
piy-3y<4+2
y(pi-3)<6
y<6/(pi-3)
C) (3^(1/2)-1)(3^(1/2)+1)x>=4*3^(1/2)x-10
(9-1)x>=4*3^(1/2)x-10
8x-4*3^(1/2)x>=-10
x(8-4*3^(1/2)>=10
x>= 5/(4-2*3^(1/2))
x>= (5*(4+2*3^(1/2))/4
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A) x-pi>=xpi
x-xpi>=pi
x(1-pi)>=pi
x>=pi/(1-pi)
B) piy-2<3y+4
piy-3y<4+2
y(pi-3)<6
y<6/(pi-3)
C) (3^(1/2)-1)(3^(1/2)+1)x>=4*3^(1/2)x-10
(9-1)x>=4*3^(1/2)x-10
8x-4*3^(1/2)x>=-10
x(8-4*3^(1/2)>=10
x>= 5/(4-2*3^(1/2))
x>= (5*(4+2*3^(1/2))/4