rozwiąż nierównosc .!xdo kwadratu -9x+20 = 0
x²-9x+20=0
Δ=b^2-4ac
Δ=81-4*20=1
x=(-b-√Δ)/2a v x=(-b+√Δ)/2a
x=(9-1)/2=4 v x=(9+1)/2=5
II sposob
ze wzorow Viete'a
x1+x2=-b/a
x1*x2=c/a
x1+x2=9
x1*x2=20
x=4 v x=5
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x²-9x+20=0
Δ=b^2-4ac
Δ=81-4*20=1
x=(-b-√Δ)/2a v x=(-b+√Δ)/2a
x=(9-1)/2=4 v x=(9+1)/2=5
II sposob
ze wzorow Viete'a
x1+x2=-b/a
x1*x2=c/a
x1+x2=9
x1*x2=20
x=4 v x=5