Rozwiąż nierówność:
(4-x²)(x⁴-7x³+10x²)≤0
(4-x²)(x⁴-7x³+10x²)=0
x²(4-x²)(x²-7x+10)=0
x²(2+x)(2-x)(x-5)(x-2)=0
x²(x+2)(x-2)²(x-5)=0
x=-2 lub x=0 lub x=2 lub x=5
0 i 2 to pierwiastki parzystokrotne, więc:
x∈(-∞;-2> U {0} U {2} U <5;+∞)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
(4-x²)(x⁴-7x³+10x²)≤0
(4-x²)(x⁴-7x³+10x²)=0
x²(4-x²)(x²-7x+10)=0
x²(2+x)(2-x)(x-5)(x-2)=0
x²(x+2)(x-2)²(x-5)=0
x=-2 lub x=0 lub x=2 lub x=5
0 i 2 to pierwiastki parzystokrotne, więc:
x∈(-∞;-2> U {0} U {2} U <5;+∞)