Rozwiąż nierówność:
a) x²<2-x
c) x-7≥5x²
d) 4x²+49≤8x
x²+x-2<0
Δ=1²-4*1*(-2)=9
√Δ=3
x₁=(-1+3)/2=2/2=1
x₂=(-1-3)/2=-4/2=-2
x∈(-2;1)
-5x²+x-7 ≥0
Δ=1²-4*(-5)*(-7)=1-140=-139
x∈R
4x²-8x+49≤0
Δ=(-8)²-4*4*49=64-784=-720
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a) x²<2-x
x²+x-2<0
Δ=1²-4*1*(-2)=9
√Δ=3
x₁=(-1+3)/2=2/2=1
x₂=(-1-3)/2=-4/2=-2
x∈(-2;1)
c) x-7≥5x²
-5x²+x-7 ≥0
Δ=1²-4*(-5)*(-7)=1-140=-139
x∈R
d) 4x²+49≤8x
4x²-8x+49≤0
Δ=(-8)²-4*4*49=64-784=-720
x∈R