Rozwiąż nierówność:
a)-x2+2x+24<0
b)x2-4x+8<0
c)x(x+6)>-9
proszę o pomoc!! ;):)
a)Δ = 4 + 96 = 10^2x1 = 4x2 = -6x ∈ (-6,4)b) Δ = 16 - 32 = -16 brak rozwiązań c) x^2 + 6x + 9Δ = 36 - 36 = 0x = -b/a = -6/2 = -3x ∈ (-∞, -3) ∨ (-3, ∞)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a)
Δ = 4 + 96 = 10^2
x1 = 4
x2 = -6
x ∈ (-6,4)
b)
Δ = 16 - 32 = -16
brak rozwiązań
c)
x^2 + 6x + 9
Δ = 36 - 36 = 0
x = -b/a = -6/2 = -3
x ∈ (-∞, -3) ∨ (-3, ∞)