Rozwiąż nierówność:9x^2 + 6x +4 < 3 (^2- oznacza 9x do kwadratu)
9x²+6x+4<3 |-3
9x²+6x+1<0
Δ=b²-4ac=6²-4*9*1=36-36=0
x=
x∈(-∞,)
:)
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9x²+6x+4<3 |-3
9x²+6x+1<0
Δ=b²-4ac=6²-4*9*1=36-36=0
x=
x∈(-∞,)
:)