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D:1+1/x>0
(x+1)/x>0⇔(x+1)*x>0
x1=-1 x2=0
x∈(-∞,-1)∨(0,+∞)
ln(1+1/x)≤ln(1) e>1 f. rosnaca
1+1/x≤1
1/x≤0⇒x<0 ∧D
x∈(-∞,-1)
Pozdr
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