rozwiąż nierówność :
a)
b)
a) /√3
x - 6/√3 < -2x
3x < 6/√3
x < 2/√3
√2x + 4 < 2√2x - 8 /√2
x + 4/√2 < 2x - 8/√2
12/√2 < x
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a) /√3
x - 6/√3 < -2x
3x < 6/√3
x < 2/√3
b)
√2x + 4 < 2√2x - 8 /√2
x + 4/√2 < 2x - 8/√2
12/√2 < x