April 2019 0 8 Report
Rozwiąż nierówność:
a) \sqrt{x^2-4x+4} + \sqrt{4x^2+4x+1} \ \textless \ 4-x
b) 2\sqrt{x^2+2x+1}\ \textgreater \ x+4




Próbowałam tak:

\sqrt{x^2-4x+4} + \sqrt{4x^2+4x+1} \ \textless \ 4-x \\\\\sqrt{(x-2)^2} + \sqrt{(2x+1)^2} \ \textless \ 4-x \\\\x-2+2x+1\ \textless \ 4-x \\4x\ \textless \ 5 \\\\x\ \textless \ \frac{5}{4}

Ale to jest złe rozwiązanie.
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