rozwiąż nierówność a) 3x²-2x-1>0
Δ=4-4*3*(-1)=4+12=16
√Δ=4
x₁=(2-4)/2*3=-2/6=-1/3
x₂=(2+4)/2*3=6/6=1
rysujemy parabole ramionami do gory
x∈(-∞,-1/3) u (1,∞)
b) 2x²+(x+1)²<8x+1
2x²+x²+2x+1-8x-1<0
3x²-6x<0
3x(x-2)<0
3x=0 v x-2=0
x=0 v x=2 rysujemy parabole ramionami do gory
x∈(0,2)
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rozwiąż nierówność
a) 3x²-2x-1>0
Δ=4-4*3*(-1)=4+12=16
√Δ=4
x₁=(2-4)/2*3=-2/6=-1/3
x₂=(2+4)/2*3=6/6=1
rysujemy parabole ramionami do gory
x∈(-∞,-1/3) u (1,∞)
b) 2x²+(x+1)²<8x+1
2x²+x²+2x+1-8x-1<0
3x²-6x<0
3x(x-2)<0
3x=0 v x-2=0
x=0 v x=2 rysujemy parabole ramionami do gory
x∈(0,2)
3x²-2x>-1 /:2
1,5x²-x>-0,5
b) 2x²+(x+1)²<8x+1
2x²+x²+1<8x+1 /-1
3x²<8x