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|x|<a ⇔ x>-a ∧ x<a
|x|>a⇔ x<-a ∨ x>a
|3-5x| - 2 > 0
|3-5x| > 2
3-5x<-2 ∨ 3-5x>2
5x>5 ∨ 5x<1
x>1∨ x<1/5⇒x∈(-∞,1/5)∨(5,+∞)
patrz zalacznik
b jak w/w
|1-3x|<4
1-3x>-4∧1-3x<4
3x<5 ∧ 3x>-3
x<5/3 ∧ x>-1 ⇒x∈(-1,5/3)