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1*(2+√3)/(2-√3)(2+√3)=
(2+√3)/(4-3)=
(2+√3)/1=
2+√3
2+√3, bo (a-b)(a+b)=a²-b²
(2+√3) / [(2-√3)(2+√3)] = (2+√3) / (4-3) = 2+√3
2-√3 obustronnie mnozymy razy 2+√3 bo a²-b²=(a-b)(a+b)
2+√3
(2-√3)(2+√3)
2+√3
4-3
2+√3
= 2+√3
1