Rozwiąż: a) log5 + log(x+10) = 1 - log(2x-1) + log(21x-20)
log5+log(x+10)=1-log(21x-20)
log5+logx+log10=1-log21x-log20
log15+logx=1-log21x-log20
log35+logx=1-log21x
log35=1-log20x
log35+log20x=1
1=log35+log20x
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log5+log(x+10)=1-log(21x-20)
log5+logx+log10=1-log21x-log20
log15+logx=1-log21x-log20
log35+logx=1-log21x
log35=1-log20x
log35+log20x=1
1=log35+log20x