Rozłóż wielomian w (x) x⁴-5x³+6x² na czynniki :) Proszę pomóżciee ! ;**
f(x) = x⁴ -5x³ + 6x²
f(x) = x²(x² - 5x + 6)
Δ = 25 - 24 = 1
√Δ = 1
x1 = (5 - 1)/2 = 4/2 = 2
x2 = (5 + 1)/2 = 6/2 = 3
x² - 5x + 6 = (x - 2)(x - 3)
f(x) = x²(x - 2)(x - 3) ------------- odpowiedź
W(x)=x⁴-5x³+6x²=x²(x²-5x+6)=x²(x-2)(x-3)
Δ=(-5)²-4·6=1
x₁=2
x₂=3
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f(x) = x⁴ -5x³ + 6x²
f(x) = x²(x² - 5x + 6)
Δ = 25 - 24 = 1
√Δ = 1
x1 = (5 - 1)/2 = 4/2 = 2
x2 = (5 + 1)/2 = 6/2 = 3
x² - 5x + 6 = (x - 2)(x - 3)
f(x) = x²(x - 2)(x - 3) ------------- odpowiedź
W(x)=x⁴-5x³+6x²=x²(x²-5x+6)=x²(x-2)(x-3)
Δ=(-5)²-4·6=1
x₁=2
x₂=3