Odpowiedź:
w(x)= 3x³-4x²-4x+3=3(x³+1)-4x(x+1)=3(x+1)(x²-x+1)-4x(x+1)=[3(x²-x+1)-4x](x+1)=(3x²-7x+3)(x+1)
w(x)= 64x³+12x²-3x-1=(64x³-1)-3x(4x-1)=[(4x-1)(16x²+4x+1)]-3x(4x-1)=(4x-1)(16x²+x+1)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Odpowiedź:
w(x)= 3x³-4x²-4x+3=3(x³+1)-4x(x+1)=3(x+1)(x²-x+1)-4x(x+1)=[3(x²-x+1)-4x](x+1)=(3x²-7x+3)(x+1)
w(x)= 64x³+12x²-3x-1=(64x³-1)-3x(4x-1)=[(4x-1)(16x²+4x+1)]-3x(4x-1)=(4x-1)(16x²+x+1)