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1/ [(x+2)(x-2)²] - 1/[(x-2)(x+2) -2/(x-2)²=0
D=R-{-2;2}
1/[(x+2)(x-2)²] - (x-2) / [(x+2)(x-2)² -[2(x+2) / [(x+2)(x-2)²] II* [(x+2)(x-2)²]
1-(x-2)-2(x+2)=0
1-x+2-2x-4=0
-3x-1=0
-3x=1
x= - 1/3 ∈D