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∫x=3-y
∫x=3-y
∫5y-(3-y)=3
∫x=3-y
∫5y-3+y=3
∫x=3-y
∫6y=6
y=1
x=3-y
x=3-1
x=2
∫y=1
∫x=2
x=3-y
5(3-y)=3
15-5y=3
-5y=-12/-5
y=2,5
x=3-2.5
x= 0,5
x=0,5
y=2,5
Jeśli mozesz to dodaj moją odp. do najlepszych z gory dzieki;P