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a²=4+16
a²=20
a=2∫5
16+4=x²
x²=20
x=2√5
x - długość boku
x- długość boku rombu
Z twr Pitagorasa :
2∧2 + 4∧2= x∧2
20=x∧2 /√
x= √20
x=2√5 cm