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x(x+2)(x-3)+9x²
(x²+2x)(x-3)+9x²
x³-3x²+2x²-6x+9x²
x³+8x²-6x
x(x²+8x-6)=0
x(x + 2)(x - 3) + 9x² = En los dos primeros parentesis se aplica
productos notables (x + a)(x - b) =
x² +(a - b)x + (a)(b)
x(x² + (2 - 3)x + (2)(-3)) + 9x² =
x(x² + (- x) + ( -6)) + 9x² =
x(x² - x - 6) + 9x² =
x³ - x² - 6x + 9x² =
x³ +8x² - 6x
Rspuesta.
x³ + 8x² - 6x