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frente=x-12
fondo= x
perimetro 56
perimetro de un rectángulo
P=2(base)+2 (altura)
56=2(x)+2 (x-12)
56=2x+2x-24
56= 4x-24
56+24=4x
80=4x
80/4=x
20=x
las dimensiones del terreno es
frente=x-12
frente=20-12=8
fondo= x
fondo= 20