Średnica podstawy walca o objętości 0,36 Pi dm szesciennych ma 12cm.Jaką wysokość ma ten walec?
V = Pp*H
2r = 12
r=6
0,36*Pi = Pi 6^2*H
0,36*Pi = 36Pi H / 36 Pi
H = 0, 01
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V = Pp*H
2r = 12
r=6
0,36*Pi = Pi 6^2*H
0,36*Pi = 36Pi H / 36 Pi
H = 0, 01