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masa
masa
44u*2=88u Xg 44gC2H5OH + 3 O2 ----> 2 CO2 + 3 H2O
46u 88u Xg---------------44g
46u-------------88u
46u*44g 2024
---------- = --------- = 23[g]
88u 88
Odp. Tej reakcji uległo 23g etanolu.