Quis Math
Tingkat kesukaran : Difficult
TTM(Tata Tertib Menjawab)
1. Dilarang copast
2. Dengan cara
3. Tidak boleh spam
Bila
dan untuk 
maka nilai ![[sin~x( \frac{sin^{3}x~-~cos^{3}~x }{sin^{2}~x~-~\frac{1}{2} sin~2x} )- \frac{1}{2} sin~2x]^{2015}](https://tex.z-dn.net/?f=+%5Bsin%7Ex%28+%5Cfrac%7Bsin%5E%7B3%7Dx%7E-%7Ecos%5E%7B3%7D%7Ex+%7D%7Bsin%5E%7B2%7D%7Ex%7E-%7E%5Cfrac%7B1%7D%7B2%7D+sin%7E2x%7D+%29-+%5Cfrac%7B1%7D%7B2%7D+sin%7E2x%5D%5E%7B2015%7D+ "[sin~x( \frac{sin^{3}x~-~cos^{3}~x }{sin^{2}~x~-~\frac{1}{2} sin~2x} )- \frac{1}{2} sin~2x]^{2015}")
adalah....
Tingkat kesukaran : Difficult
TTM(Tata Tertib Menjawab)
1. Dilarang copast
2. Dengan cara
3. Tidak boleh spam
Bila
Kilos
2 votes
Thanks 2
Brillianttt
sip...
ImmanuelSinaga
![.~~~~~~~~~~~~~~~~~~~~~~~~~~\boxed{\bold{[sin~x~(\displaystyle\frac{sin^3x~-~cos^3x}{sin^2x~-~\frac{1}{2}sin~2x})-\frac{1}{2}sin~2x]^{2015}}} \\ \\ \text{jawab~:} \\ \boxed{sin~2x~=~2~sin~x~cos~x} \\ \\ \bold{[sin~x~(\displaystyle\frac{sin^3x~-~cos^3x}{sin^2x~-~sin~x~cos~x})-\frac{1}{2}sin~2x]^{2015}} \\ \\ \bold{[\not{sin~x}~(\displaystyle\frac{sin^3x~-~cos^3x}{\not{sin~x}~(sin~x~-~cos~x)})-\frac{1}{2}sin~2x]^{2015}}](https://tex.z-dn.net/?f=.%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%5Cboxed%7B%5Cbold%7B%5Bsin%7Ex%7E%28%5Cdisplaystyle%5Cfrac%7Bsin%5E3x%7E-%7Ecos%5E3x%7D%7Bsin%5E2x%7E-%7E%5Cfrac%7B1%7D%7B2%7Dsin%7E2x%7D%29-%5Cfrac%7B1%7D%7B2%7Dsin%7E2x%5D%5E%7B2015%7D%7D%7D+%5C%5C+%5C%5C+%5Ctext%7Bjawab%7E%3A%7D+%5C%5C+%5Cboxed%7Bsin%7E2x%7E%3D%7E2%7Esin%7Ex%7Ecos%7Ex%7D+%5C%5C+%5C%5C+%5Cbold%7B%5Bsin%7Ex%7E%28%5Cdisplaystyle%5Cfrac%7Bsin%5E3x%7E-%7Ecos%5E3x%7D%7Bsin%5E2x%7E-%7Esin%7Ex%7Ecos%7Ex%7D%29-%5Cfrac%7B1%7D%7B2%7Dsin%7E2x%5D%5E%7B2015%7D%7D+%5C%5C+%5C%5C+%5Cbold%7B%5B%5Cnot%7Bsin%7Ex%7D%7E%28%5Cdisplaystyle%5Cfrac%7Bsin%5E3x%7E-%7Ecos%5E3x%7D%7B%5Cnot%7Bsin%7Ex%7D%7E%28sin%7Ex%7E-%7Ecos%7Ex%29%7D%29-%5Cfrac%7B1%7D%7B2%7Dsin%7E2x%5D%5E%7B2015%7D%7D ".~~~~~~~~~~~~~~~~~~~~~~~~~~\boxed{\bold{[sin~x~(\displaystyle\frac{sin^3x~-~cos^3x}{sin^2x~-~\frac{1}{2}sin~2x})-\frac{1}{2}sin~2x]^{2015}}} \\ \\ \text{jawab~:} \\ \boxed{sin~2x~=~2~sin~x~cos~x} \\ \\ \bold{[sin~x~(\displaystyle\frac{sin^3x~-~cos^3x}{sin^2x~-~sin~x~cos~x})-\frac{1}{2}sin~2x]^{2015}} \\ \\ \bold{[\not{sin~x}~(\displaystyle\frac{sin^3x~-~cos^3x}{\not{sin~x}~(sin~x~-~cos~x)})-\frac{1}{2}sin~2x]^{2015}}")
![\text{menjadi~:} \\ \\ \bold{[(\displaystyle\frac{sin^3x~-~cos^3x}{sin~x~-~cos~x})-\frac{1}{2}sin~2x]^{2015}} \\ \\ \text{kita punya identitas :} \\ \boxed{\bold{a^3~-~b^3~=~(a~-~b)~(a^2~+~ab~+~b^2)}} \\ \text{kita ubah menjadi~:} \\ \\ \bold{[(\displaystyle\frac{\not{(sin~x~-~cos~x)}(sin^2x~+~sin~x~cos~x~+~cos^2x)}{\not{sin~x~-~cos~x}})-\frac{1}{2}sin~2x]^{2015}} \\ \\ \text{kita punya identitas ~}\bold{~~sin^2x+cos^2x~=~1} \\ \text{Maka menjadi~:} \\ \bold{[1~+~sin~x~cos~x~-~sin~x~cos~x]^{2015}}](https://tex.z-dn.net/?f=%5Ctext%7Bmenjadi%7E%3A%7D+%5C%5C+%5C%5C+%5Cbold%7B%5B%28%5Cdisplaystyle%5Cfrac%7Bsin%5E3x%7E-%7Ecos%5E3x%7D%7Bsin%7Ex%7E-%7Ecos%7Ex%7D%29-%5Cfrac%7B1%7D%7B2%7Dsin%7E2x%5D%5E%7B2015%7D%7D+%5C%5C+%5C%5C+%5Ctext%7Bkita+punya+identitas+%3A%7D+%5C%5C+%5Cboxed%7B%5Cbold%7Ba%5E3%7E-%7Eb%5E3%7E%3D%7E%28a%7E-%7Eb%29%7E%28a%5E2%7E%2B%7Eab%7E%2B%7Eb%5E2%29%7D%7D+%5C%5C+%5Ctext%7Bkita+ubah+menjadi%7E%3A%7D+%5C%5C+%5C%5C+%5Cbold%7B%5B%28%5Cdisplaystyle%5Cfrac%7B%5Cnot%7B%28sin%7Ex%7E-%7Ecos%7Ex%29%7D%28sin%5E2x%7E%2B%7Esin%7Ex%7Ecos%7Ex%7E%2B%7Ecos%5E2x%29%7D%7B%5Cnot%7Bsin%7Ex%7E-%7Ecos%7Ex%7D%7D%29-%5Cfrac%7B1%7D%7B2%7Dsin%7E2x%5D%5E%7B2015%7D%7D+%5C%5C+%5C%5C+%5Ctext%7Bkita+punya+identitas+%7E%7D%5Cbold%7B%7E%7Esin%5E2x%2Bcos%5E2x%7E%3D%7E1%7D+%5C%5C+%5Ctext%7BMaka+menjadi%7E%3A%7D+%5C%5C+%5Cbold%7B%5B1%7E%2B%7Esin%7Ex%7Ecos%7Ex%7E-%7Esin%7Ex%7Ecos%7Ex%5D%5E%7B2015%7D%7D "\text{menjadi~:} \\ \\ \bold{[(\displaystyle\frac{sin^3x~-~cos^3x}{sin~x~-~cos~x})-\frac{1}{2}sin~2x]^{2015}} \\ \\ \text{kita punya identitas :} \\ \boxed{\bold{a^3~-~b^3~=~(a~-~b)~(a^2~+~ab~+~b^2)}} \\ \text{kita ubah menjadi~:} \\ \\ \bold{[(\displaystyle\frac{\not{(sin~x~-~cos~x)}(sin^2x~+~sin~x~cos~x~+~cos^2x)}{\not{sin~x~-~cos~x}})-\frac{1}{2}sin~2x]^{2015}} \\ \\ \text{kita punya identitas ~}\bold{~~sin^2x+cos^2x~=~1} \\ \text{Maka menjadi~:} \\ \bold{[1~+~sin~x~cos~x~-~sin~x~cos~x]^{2015}}")
1 votes
Thanks 1
Brillianttt
best-nya buat @kilos ya.....
Brillianttt
btw... nggak ada quis lagi kah????
ImmanuelSinaga
saya sibuk sekolah tadi, ada kuis kok. siap - siap yah :v :v
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