Q.
Carilah jumlah deret geometri dengan suku pertama 4, suku terakhir 972 dan rasionya = 3
Carilah jumlah deret geometri dengan suku pertama 4, suku terakhir 972 dan rasionya = 3
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Penjelasan dengan langkah-langkah:
a = 4
r = 3
Un = 4 × 3ⁿ-¹
972 = 4 × 3ⁿ-¹
3ⁿ-¹ = 972
4
3ⁿ-¹ = 243
3ⁿ-¹ = 243
3ⁿ-¹ = 3^5
n = 1 + 5
S6 = 4 × (3^6 – 1)
3 – 1
S6 = 4 × (729 – 1)
2
S6 = 2 × 728
S6 = 1.456