Respuesta:
(22.5 g) CH4
* n = -------------------------- = 1.41 moles
16 g/mol CH4
* temperatura : 27°C + 273°K = 300°K
-se usa el PV=nRT
se despeja
nRT
V = -----------
P
(1.41 mol) x (0.082 atm Lt/ ºK mol) x (300 ºK)
V = .................................................................................................= 33.03 Litros
1.05 atm
Explicación:
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Respuesta:
(22.5 g) CH4
* n = -------------------------- = 1.41 moles
16 g/mol CH4
* temperatura : 27°C + 273°K = 300°K
-se usa el PV=nRT
se despeja
nRT
V = -----------
P
(1.41 mol) x (0.082 atm Lt/ ºK mol) x (300 ºK)
V = .................................................................................................= 33.03 Litros
1.05 atm
Explicación: