Cuál es el peso de 7 litros de gas amoniaco NH3 en condiciones normales de presion y temperatura?
Mm NH3 = 17 g/mol
1. calcular moles
1 mol ----- 22.4 L
x ----- 7 L
X = 0.312 mol de NH3
2. calcular gramos de NH3
n = masa / Mm
masa = 0.312 mol x 17 g/mol
masa = 5.304 g de NH3
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Aplicar la ley de los gases ideales
V x P = n x R x t
V = 7 L
P = 1 atm
R = 0.0821 (L atm /molK)
T = 273 K
n = ?
1. calcular n = ?
n = (7 L x 1 atm) / ( 0.0821 (L atm /molK) x 273 K)
n = 0.312 moles
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Cuál es el peso de 7 litros de gas amoniaco NH3 en condiciones normales de presion y temperatura?
Mm NH3 = 17 g/mol
1. calcular moles
1 mol ----- 22.4 L
x ----- 7 L
X = 0.312 mol de NH3
2. calcular gramos de NH3
n = masa / Mm
masa = 0.312 mol x 17 g/mol
masa = 5.304 g de NH3
```````````````````````````````````````````````````````````````````````
Aplicar la ley de los gases ideales
V x P = n x R x t
V = 7 L
P = 1 atm
R = 0.0821 (L atm /molK)
T = 273 K
n = ?
1. calcular n = ?
n = (7 L x 1 atm) / ( 0.0821 (L atm /molK) x 273 K)
n = 0.312 moles
2. calcular gramos de NH3
n = masa / Mm
masa = 0.312 mol x 17 g/mol
masa = 5.304 g de NH3