Question

Pusat dan jari jari lingkaran x^2+y^2-4x-6y-12=0 adalah..

Answer 1

A=-4, b=-6, c=-12 ~ pusat =((-1/2). a),((-1/2).b) =((-1/2).(-4)),((-1/2).(-6)) =(2,3) ~jari2= r2 = a2 + b2 - c = (2.2) + (3.3) - (-12) r= akar 4 + 9 + 12 = akar 25 r = 5 semoga bisa membantu