punkty A(2a, -b) B(-3a, b+1) należą do wykresu funkcji liniowej f opisanej wzorem f(x)=-x+3 a) oblicz a i b
A = ( 2a; - b) , B = ( - 3a ; b + 1)
f(x) = - x + 3
zatem
f( 2a) = - 2 a + 3 = - b
f( - 3a) = 3a + 3 = b + 1
Mamy
-2 a + 3 = - b => b = 2 a - 3
3a + 3 = b + 1
--------------------
b = 2 a - 3
3a + 3 = ( 2 a - 3) + 1
------------------------------
3a - 2 a = -2 - 3
------------------------
a = - 5
b = 2*(-5) - 3 = - 13
====================
Odp. a = - 5 ; b = - 13
======================
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A = ( 2a; - b) , B = ( - 3a ; b + 1)
f(x) = - x + 3
zatem
f( 2a) = - 2 a + 3 = - b
f( - 3a) = 3a + 3 = b + 1
Mamy
-2 a + 3 = - b => b = 2 a - 3
3a + 3 = b + 1
--------------------
b = 2 a - 3
3a + 3 = ( 2 a - 3) + 1
------------------------------
b = 2 a - 3
3a - 2 a = -2 - 3
------------------------
a = - 5
b = 2*(-5) - 3 = - 13
====================
Odp. a = - 5 ; b = - 13
======================