Punkty A iB sa symetryczne wzgledem osi x.Oblicz a i b wiedzac ,ze: A=(3a-1,2b) B=(a-1,b+3)
A=(3a-1,2b)
B=(a-1,b+3)
3a-1=a-1
3a-a=-1+1
2a=0
a=0
2b=-(b+3)
2b=-b-3
2b+b=-3
3b=-3
b=-1
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A=(3a-1,2b)
B=(a-1,b+3)
3a-1=a-1
3a-a=-1+1
2a=0
a=0
2b=-(b+3)
2b=-b-3
2b+b=-3
3b=-3
b=-1