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d - przekątna kwadratu
P - pole kwadratu
d = a√2
d = a + 2
a√2 = a +2
(a√2 - a) = 2
a(√2-1) = 2
a = 2/(√2-1)
usuwam niewymierność
a = 2√2 + 2 cm
P = a²
P = (2√2 + 2)²
P = (2√2)² + 2*2√2*2 + (2)²
P = 4*2 + 8√2 + 4
P = 8+4 +8√2
P = 12 + 8√2 cm²
Odp. Pole kwadratu wynosi 12 + 8√2 cm²