przekształć do postaci sumy algebraicznej i oblicz wartość wyrażenia:
-2(x+4-y+z)x=?? dla x=3 y=-2 z=-1
...=(-2x-8+2y-2z)x=-2x^2-8x+2xy-2xz
-2*3^2-8*3+2*3*(-2)-2*3*(-1)=-18-24-12+6=-48
-2(x+4-y+z)x=(-2x-8+2y-2z)x=(-2x)x -8x +2xy -2xz = -2x2 -8x +2xy - 2xz=-18 -24 -12 +6=-48
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...=(-2x-8+2y-2z)x=-2x^2-8x+2xy-2xz
-2*3^2-8*3+2*3*(-2)-2*3*(-1)=-18-24-12+6=-48
-2(x+4-y+z)x=(-2x-8+2y-2z)x=(-2x)x -8x +2xy -2xz = -2x2 -8x +2xy - 2xz=-18 -24 -12 +6=-48