Question

Przedstaw w postaci jednej potęgi
a)2^4*8^4 g) 16*8^6 m)625^3*125
b)32^2*4^3 h)81^3:3^7 n) 16^2*8^3
c)5^8*25^3 i) 49^5:7^3 o)27^3*9^4
d)9^2*3^3 j)64^3:32^2 p)8^3:2^2
e)125^4*25^3 k)27^6:243
f)27^4:9^5 l)128^3:64^2



PROSZĘ TO NA JUŻ PLISSSSSSSS

Answer 1

A)2^4*8^4  = (2*8)^4 = 16^4 = (2^4)^4 = 2^16
g) 16*8^6 = 2^4 * (2^3)^6 = 2^4 * 2^18 = 2^(4+18)=2^20
m)625^3*125 = 5^4 * 5^3 = 5^7
b)32^2*4^3  = (2^5)^2 * (2^2)^3 = 2^10 * 2^6 = 2^16
h)81^3:3^7 = (3^4)^3 : 3^7 = 3^12 : 3^ 7 = 3^(12-7)=3^5
 n) 16^2*8^3 = (2^4)^2 * (2^3)^3 = 2^8 * 2^9 = 2^17
c)5^8*25^3 = 5^8 * (5^2)^3 = 5^8 * 5^6 = 5^14
 i) 49^5:7^3 = (7^2)^5 : 7^3 = 7^10 :7^3 = 7^7
o)27^3*9^4 = (3^3)^3 * (3^2)^4 = 3^9 * 3^8 = 3^17
d)9^2*3^3 = (3^2)^2 * 3^3 = 3^4 * 3^3 = 3^7
 j)64^3:32^2 =(2^6)^3 : (2^5)^2 = 2^18 : 2^10 = 2^8
p)8^3:2^2= (2^3)^3 : 2^2 = 2^9 : 2^2 = 2^7
e)125^4*25^3 = (5^3)^4 * (5^2)^3 = 5^12 * 5^6 = 5^18
 k)27^6:243 = (3^3)^6 : 3^5 = 3^18 : 3^5 = 3^13
f)27^4:9^5 = (3^3)^4 * (3^2)^5 = 3^12 * 3^10 = 3^22
 l)128^3:64^2 = (2^7)^3 :(2^6)^2 = 2^21 : 2^12 = 2^9