przedstaw w postaci iloczynu podaną sumę:
1.) ac + bc + ad + bd
2) 2a + 2b + ac + bc
3) 3ac - 3bc + ad - bd
4) -a + b + ac - bc
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1.ac+bc+ad+bd= c(a+b)+ d(a+b)= (c+d)(a+b)
2.2a+2b+ac+bc= 2(a+b)+ c(a+b)= (2+c)(a+b)
3.3ac-3bc+ad-bd= 3c(a-b)+ d(a-b)= (3c+d)(a-b)
4.-a+b+ac-bc=-(a-b)+c(a-b)= (-1+c)(a-b)