Przedstaw w postaci iloczynu .
a) (x+y)*a+(x+y)*b =
b) 3(z-y)-a(z-y) =
c) (m-1)(k-1)+(k-1)(m+1) =
d) (a-1)(b+c)-(a-1)(b-c) =
na dzisiaj ;] jbc Matematyka z plusem zad.12 str.162
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a)(x + y) * a + (x + y) * b =
= (x + y)(a + b)
b)
3(z - y) - a(z - y) =
= (3 - a)(z - y)
c)
(m - 1)(k - 1) + (k - 1)(m + 1) =
= (k - 1)(m - 1 + m + 1) =
= (k - 1)*2m
d)
(a - 1)(b + c)-(a - 1)(b - c ) =
= (a - 1) [b + c - (b - c)] =
= (a - 1) (b + c - b + c) =
= (a - 1)*2c