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x²+8x+15
Δ=64-4*1*15=4
√Δ=2
x'= = -3
x"= = -5
x²+6x+5
Δ=36-4*1*5=16
√Δ=4
x'== -5
x"== -1
x+3=3x-3
2x=6
x=3
e)
4(2-1)=(x-1)(x-1)
8-4=x²-x-x+1
4=x²-2x+1
x²-2x-3=0
Δ=(-2)²-4*1*(-3)=16
√Δ=4
x'=
x"=
f)
3(x+1)=(x+2)(x+2)
3x+3=x²+2x+2x+4
0=x²+4x+4-3x-3
0=x²+x+1
Δ=1²-4*1*1= -3
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