Question

prosze rozwiazcie daje duzo pkt

Answer 1

= 2/(2+√3) * √3+1/ (3√3 -1) +( 2√3 + 5)/13 =

= 2/(2+√3) *(2-√3) * √3 + 1 /(3√3 - 1)(3√3 + 1) +( 2√3 + 5)/13 =

= 2/(4-3) *(√3+1)/(9*3-1) +( 2√3 + 5)/13 =

=2*(√3+1)/18+( 2√3 + 5)/13=

= (√3+1)/9 +( 2√3 + 5)/13=

=13(√3+1)/117 + 9(2√3+5)/117 =

= [(13(√3+1) + 9(2√3+5)]/117