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Pp=a²√3 / 4
Pp=6²√3 / 4 =36√3/4=9√3
V=1/3*Pp*H
V=1/3*9√3*8=3√3*8=24√3
a = 6 cm
H= 8 cm
V = ? [cm³]
V = 1/3Pp*H
Pp = a²√3/4
Pp = (6 cm)²√3/4
Pp = 9√3 cm²
V = 1/3*(9√3 cm²)*(8 cm)
V = 24√3 cm³
Odp: Objętość ostrosłupa wynosi 24√3 cm³.
a√3/2 czyli 6√3/2=3√3
Pp trójkąta w podstawie =a*h/2= 6*3√3/2= 18√3/2=9√3
V=Pp*h/3=9√3*8/3=72√3/3=24√3