prosze pilnie o rozwiazanie
-2·(-0,5)²+(-2)
________________=
-0,1·[-1,3+6·(-0,2)]
______________= kreska ułamkowa
-2x0,25+(-2)
___________=
-0,1x(-1,3+(-1,2)
-0,5+(-2)
-0,1x(-2,5)
-2,5
_____= -2,5:0,25=-10
0,25
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-2x0,25+(-2)
___________=
-0,1x(-1,3+(-1,2)
-0,5+(-2)
___________=
-0,1x(-2,5)
-2,5
_____= -2,5:0,25=-10
0,25