prosze obliczyc delte i miejsca zerowe:
-x²-3x+28=0
Δ = 9 + 4 * 28 = 121
√Δ = √121 = 11
x₁ = (3 - 11)/-2 = -8/-2 = 4
x₂ = (3 + 11)/-2 = 14/-2 = -7
delta=9+112=121
x1=3-11/-2=4
x2=3+11/-2=-7
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Δ = 9 + 4 * 28 = 121
√Δ = √121 = 11
x₁ = (3 - 11)/-2 = -8/-2 = 4
x₂ = (3 + 11)/-2 = 14/-2 = -7
delta=9+112=121
x1=3-11/-2=4
x2=3+11/-2=-7